@qDISTANCE TUTORIAL -- PART 1.\nThis is a Tutorial on Distance Problems. If you find a question confusing, use the `HELP' key.@pIf the Tutorial seems too easy, use the `Skip Problem' key.\n    (Any key to continue.)@hThere are always two levels of `HELP' available. The second level provides the correct answer.@hThe `Skip Problem' key will take you to the next problem, or to the next part of the Tutorial.@i(0)@jDistance Problems generally compare the motion of two objects:@dg04&d(5,Rate)&d(10,Time) &d(15,Dist) &c(2,Dog)&c(3,Cat)&d(4,Total)&d(0,How far apart are the pets after 1 hour? When will they meet?\nWhen will the Dog catch the Cat?)@jDistance Problems are easy to diagram, and, therefore, help you to picture algebraic relationships.@dcars&d(0,Two cars start at the same time headed in opposite directions.)@drun&d(0,Two runners start at different times\, headed in the same direction.)@dswimmer&d(0,Or\, two swimmers start swimming towards each other at the same time.) @jTo solve Distance Problems you must know Rate, Time, and Distance for each object involved.@dg05&d(4,Rate)&d(8,Time)&d(12,Dist)&d(0,The general equation that relates key quantities in a word problem is called an `Equation Idea'.&qRate, Time, and Distance&q)&d(0,The `Equation Idea' to find the Distance an object travels is:\n      Rate * Time = Distance.)&c(16,Rate * Time = Distance)&d(0,If you travel at a certain Rate for a set amount of Time\, the Distance travelled is:  Rate * Time.) &d(1,Unit/Meas)&c(2,Object)@jDistance problems use different Units of Measure.&d(0,)&d(0,Make sure Units of Measure are uniform. If Rate is `ft/sec'\, then Time is in seconds and Distance is in feet.)&d(5,mi/hr)&d(9,hr)@pEnter the Unit of Measure for Distance. Note: Rate is in miles per hour (mi/hr), and Time is in hours (hr).@hRate of speed is measured as miles travelled every hour, so Distance would be measured in miles.@hThe abbreviation for miles is `mi'. Enter `mi' and press the <Return> key.@i(13,c2,mi)@s&d(5,me/hr)&d(9,hr)&d(13,)@pEnter the Unit of Measure for Distance, if Rate is in meters per hour (me/hr), and Time is in hours (hr).@hRate of speed is measured as meters travelled every hour, so Distance would be measured in meters.@hThe abbreviation for meters is `me'. Enter `me' and press the <Return> key.@i(13,c2,me)&d(5,km/hr)&d(9, )&d(13, )@pEnter the Unit of Measure for Distance, if Rate is in kilometers per hour (km/hr).@hRate of speed is measured as kilometers travelled every hour, so Distance would be measured in kilometers.@hThe abbreviation for kilometers is `km'. Enter `km' and press the <Return> key.@i(13,c2,km)&d(9,min)&d(0,If Time is given in minutes, there is no unit in common with the Rate. How can you fix this?)&d(0,Use hours (hr) as the Unit of Measure, and multiply the Time given in the problem by 60.)&d(9,hr)&d(10,__ * 60)&d(0,It is essential to have all Units of Measure agree.) */@c@jHere is some practice in simple Distance Problems with one object.@pAt any time, to proceed to the next part of the Tutorial, use the "Skip Problem" option. (Any key to continue.)@hThere are three parts to the Distance Tutorial.@hThe "Skip Problem" option takes you to the next problem, or to the next part of the Tutorial.@i(0) @jA Blue Car ...&c(2,Blue Car)&d(0,\f06How fast does it go?\n\f06How long does it travel?\n\f06How far does it go?)@jA Blue Car travels at 60 miles per hour (mi/hr) ...&d(5,mi/hr)@p\f08Enter the Rate:\n\f08How fast does it go?\nRemember to use the `HELP' key.@h`60 mi/hr' means that the car goes 60 miles the 1st hour, another 60 miles the 2nd hour, and so on.@hEnter `60 mi/hr' and press the <Return> key.@i(6,i,60)&d(6,60 mi/hr) @s&d(0,Rate of speed, in this problem, is determined by the miles travelled in 1 hour (mi/hr).)@jA Blue Car travels at 60 miles per hour (mi/hr) for 1 hour (hr).&d(9,hr)@p\f06Enter the Time:\n\f06How long does it travel?@hThe car travels for 1 hour.\nEnter `1 hr'.@hThe car travels for 1 hour.\nEnter `1 hr' and press the <Return> key.@i(10,i,1)&d(10,1 hr)&d(0,Time is usually measured in hours (hr)\, minutes (min)\, or seconds (sec).)@jA Blue Car travels at 60 miles per hour (mi/hr) for 1 hour (hr). How many miles (mi) does it go?&d(13,mi)@pEnter a variable for the unknown:  (How far does it go?)@hUse a variable, such as `x' to represent the distance travelled.@hEnter the letter `x' and press the <Return> key.@i(14,i,&v)@s&c(16,Equation Idea)&d(0,The Equation Idea needs to be entered. (In the Tutorial\, the program does this for you.))&c(16,Rate  *  Time  =  Distance)&d(0,Next, it is necessary to substitute expressions for Rate\, Time\, and Distance in the Equation Idea.)&c(16,60   *  Time  =  Distance)&d(0,The Rate is 60 mi/hr, so `60' is substituted for `Rate'.)&c(16,60   *   1    =  Distance)&d(0,The Time is 1 hr, so `1' is substituted for `Time'.)&c(16,60   *   1    =     &v)&d(0,And Distance is represented by the variable `&v'\, so `&v' is substituted for `Distance'.)&c(16,60 = &v)&d(0,Next\, the equation is solved for `&v'.)@pEnter the answer on the grid.@h60 * 1 = &v, so &v = `60'.@hEnter `60' and press the <Return> key.@i(14,i,60)&d(14,60)&d(0,If a car travels 60 miles each hour for one hour\, then it goes 60 miles.) @jAt 60 miles per hour, how far does the Blue Car go in one half hour?&d(10,1/2 hr)&d(14,&v)&d(16,)&d(0,)&d(0,If the car goes 60 miles per hour, then it travels 60 miles in one hour. In half an hour it goes half as far.)@pEnter how far the car would go in half an hour. [Remember to use the `HELP' key if you need it.]@hIf a car travels at a constant speed and goes 60 miles in an hour, it would travel 30 miles in half an hour.@hHalf of 60 is 30. Enter `30' and press the <Return> key.@i(14,i,30) @jAt 60 miles per hour, how far does the Blue car go in 1 minute?&d(10,1 min)&d(14,&v)&d(0,)@pAn hour is 60 minutes. Enter how far the car goes in a minute. [Remember to use the `HELP' key if you need it.]@hIf a car travels at a constant speed, and goes 60 miles in an hour, it would travel a mile every minute.@h60 miles divided by 60 is 1 mile. Enter `1'.@i(14,i,1) |